本文实例讲述了JavaScript使用RegExp进行正则匹配的方法。分享给大家供大家参考。具体实现方法如下：
<script type="text/javascript">
var matchedTimes = 0;
//Match one d followed by one or more b's followed by one d
//Remember matched b's and the following d
//Ignore case
myRe = new RegExp("d(b+)(d)", "ig");
// 等价于 myReg = /d(b+)(d)/ig;
myArray = myRe.exec("ecDBDsdbbdz"); // ecdbBdbsdbbdz
console.log("Regular Expression String: " + myRe.source);
console.log("Is global? " + myRe.global);
console.log("Ignore case? " + myRe.ignoreCase);
console.log("Is mulitiline? " + myRe.multiline);
console.log("------------------------------------------------");
logInfo(myArray, myRe);
myArray = myRe.exec("ecDBDsdbbdz");
logInfo(myArray, myRe);
function logInfo(myArray, myRe) {
matchedTimes++;
console.log("This is " + matchedTimes + " times match");
console.log("Original String: " + myArray.input);
console.log("Match Result Array: [" + myArray + "]");
console.log("The 0-based index of the match in the string: " + myArray.index);
console.log("The last matched characters: " + myArray[0]);
console.log("The parenthesized substring matches [1]: " + myArray[1]);
console.log("The parenthesized substring matches [2]: " + myArray[2]);
console.log("The index at which to start the next match: " + myRe.lastIndex);
console.log("-----------------------------------------------");
}
myRe2 = /^w+(d*)$/ig
console.log("myRe2: " + myRe2.source);
//console.log("myRe2 matches abc1? " + myRe2.test("abc1"));
// 加上这行跑跑看结果，因为是global匹配，所以lastIndex会改变，
//所以后面的myRe2.test("abc")当然就是false
console.log("myRe2 matches abc? " + myRe2.test("abc"));
</script>
希望本文所述对大家的javascript程序设计有所帮助。
